Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Physics (https://www.askmehelpdesk.com/forumdisplay.php?f=258)
-   -   A triangle .33 acer lot . What are the outside dimension. (https://www.askmehelpdesk.com/showthread.php?t=541652)

  • Jan 7, 2011, 03:42 PM
    vertana
    A triangle .33 acer lot . What are the outside dimension.
    I have a plot of land that is .33ac. Its shape is a perfect triangle. I would like to know the outside footage measurements of it.
  • Jan 9, 2011, 12:35 AM
    Unknown008

    It depends on what you mean by 'perfect triangle'...

    Take a look at some common ones and their names:

    Triangle - Wikipedia, the free encyclopedia
  • Jan 9, 2011, 09:49 AM
    vertana
    Comment on Unknown008's post
    It is a Right triangle
  • Jan 9, 2011, 10:06 AM
    Unknown008

    By a right triangle, I would suppose it's just the triangle that you would get by cutting a square into two equal parts along the diagonal?

    (I'm not sure what you mean by outside footage. I'll guess that it's the length of all the three sides combined. If not, let me know)

    If so, you can find it using the following formulae.

    The area of the triangle is given by half the product of the two shorter sides.

    And I'm using the conversion:
    1 acre = 43 560 square foot

    So, we get:



    This gives one side as about 170 ft (170.41127)

    The longer side is then obtained using Pythagoras' Theorem...



    The sides have length 170 ft, 170 ft and 241 ft. Add them to get the outside footage

  • All times are GMT -7. The time now is 06:57 AM.