Density of Planet
A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 1.65 hours. What is density of the planet? Assume that the planet has a uniform density.
(in kg/m^3)
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Density of Planet
A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 1.65 hours. What is density of the planet? Assume that the planet has a uniform density.
(in kg/m^3)
Susus:
Here's a hint to get you started: use good old F=ma, where F is the force of gravity between the planet and the satellite, and a is the acceleration of a mass in circular motion:
Recall that density = mass/volume, and the volume of a sphere is
Can you take it from here?
Thanks I appreciate what you are doing.. I just too much fool for understanding what I have to do now :)
Susus - please do not mark posts as unhelpful, unless it is actually in error.
The little m's cancel out- so it does not matter what the satellite's mass is.
You don't really care out big M, you only care about big M divided by R^3, because you are trying to determine the density of the planet, not its mass. If you manipulate the equations I gave you previously you can find a formula for M/R^3.
4*pi^2*r/P^2 = G*m/r^2
4*pi^2*r^3/(G*P^2) = m
Now use the definition of density as mass divided by volume.
density = d = m/v = m/[(4/3)*pi*r^3]
d = 3*pi/(G*P^2)
d= 4000 ;) thanks..
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