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-   -   Sec^6x-tan^6x = 1 3(tan^2x)(sec^2x) (https://www.askmehelpdesk.com/showthread.php?t=531803)

  • Dec 5, 2010, 08:11 AM
    Lilp22
    sec^6x-tan^6x = 1 3(tan^2x)(sec^2x)
    We're proving identifies in class, and I was kind confused on how to prove this one.
  • Dec 5, 2010, 09:17 AM
    Lilp22
    Sorry there was suppose to be a plus in that question
    sec^6x-tan^6x = 1 + 3(tan^2x)(sec^2x)
  • Feb 18, 2012, 10:53 PM
    neerajtiwari
    Left Hand Side = sec^6 x - tan^6 x
    = (sec²x - tan²x)(sec^4 x + (tan²x)(sec²x) + tan^4 x)
    = 1*(sec^4 x + (tan²x)(sec²x) + tan^4 x)
    = sec^4 x + (tan²x)(sec²x) + (tan²x)²

    = sec^4 x + (tan²x)(sec²x) + (sec²x - 1)²
    = sec^4 x + (tan²x)(sec²x) + sec^4 x - 2sec²x + 1
    = 1 + 2sec^4 x - 2sec²x + (tan²x)(sec²x)

    = 1 + 2sec²x(sec²x - 1) + (tan²x)(sec²x)
    = 1 + 2(sec²x)(tan²x) + (tan²x)(sec²x)
    = 1 + 3(tan²x)(sec²x) = Right Hand Side

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