be cosx=x^2.

Prove that this equation has exactly two radical .
how I do it?

thanks for help

What do you mean 'prove it has two radicals'?



If you graph this you have parabola. If you want the x intercepts/zeros, note where it crosses the x-axis.

You can also use Newton's method to solve for x if you want to do it algebraically.






Perform the iterations and home in on the values.

It is symmetric about the y-axis, so the solution is the positive and negative of the same value. The parabola is concave down with vertex at (0,1).

Other than that, I am sorry but I do not know to what you are referring.