lim x^2-9/x+3 = -6
x-->3
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lim x^2-9/x+3 = -6
x-->3
I think that you meant:
What happens if you factorise the denominator? :)
Please use proper grouping symbols. You are in calculus.
Are you sure there is not a typo.
x should perhaps approach -3 instead of 3?
Here's why I ask:
The numerator is a difference of two squares.
If x approached 3, the limit would be 0.
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