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-   -   How to prove this using epsilon delta lim x->3 x^2-9/x 3 = -6 (https://www.askmehelpdesk.com/showthread.php?t=525748)

  • Nov 14, 2010, 05:41 AM
    mimss
    how to prove this using epsilon delta lim x->3 x^2-9/x 3 = -6
    lim x^2-9/x+3 = -6
    x-->3
  • Nov 14, 2010, 06:47 AM
    Unknown008
    I think that you meant:


    What happens if you factorise the denominator? :)
  • Nov 14, 2010, 06:51 AM
    galactus

    Please use proper grouping symbols. You are in calculus.

    Are you sure there is not a typo.
    x should perhaps approach -3 instead of 3?

    Here's why I ask:

    The numerator is a difference of two squares.





    If x approached 3, the limit would be 0.

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