Ask Me Help Desk - Let f(x)=(x^2-1)(e^x-1). Find the value of x which give f(x)=0.

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Let f(x)=(x^2-1)(e^x-1). Find the value of x which give f(x)=0.

If either the term (x^2-1) = 0, or (e^x - 1) = 0, then f(x) = 0. This means that either of the following conditions yield f(x) = 0:

x^2 = 1, or
e^x = 1.

Can you take it from here?

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