Ask Me Help Desk - Partial fractions

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)

- Mathematics (https://www.askmehelpdesk.com/forumdisplay.php?f=199)

- - Partial fractions (https://www.askmehelpdesk.com/showthread.php?t=514702)

split this into partial fraction
z/(z^2-1)(z^2+4)

Do you mean this:

$<br /> \frac z {(z^2-1)(z^2+4)}<br />$ ?

Note that $z^2-1$ factors to $(z+1)(z-1)$ , so you need to find values of constants A, B, C, and D that sastify this:

$<br /> \frac z {(z^2-1)(z^2+4)} = \frac A {z+1} + \frac B {z-1} + \frac {Cz + D} {{z^2 + 4}<br />$

Can you take it from here?

All times are GMT -7. The time now is 07:28 AM.