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  • Oct 6, 2010, 11:03 PM
    leke10
    physic question
    a ball is thrown straight up and rises to a maximum height of 22m. At what height is the speed of the ball equal to half of its initial value?assume the ball starts at a height 2.2m above the ground
  • Oct 7, 2010, 02:51 AM
    Unknown008

    Find the initial speed first.

    Use:



    Where v is the final velocity
    u the initial velocity
    a the acceleration
    s the displacement.

    We'll take up as positive.





    So, now, you need to use the same formula, but with the final speed v as being half that speed you just found, that is 19.7/2 = 9.85 m/s.



    Find s.

    This s is the displacement above the starting height. So, add 2.2 m to this.

    Post what you get! :)

    ANS: 14.85 m + 2.2 m = 17.05 m

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