Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Math & Sciences (https://www.askmehelpdesk.com/forumdisplay.php?f=402)
-   -   Factor 6x^4-18x^3 12x^2 completely (https://www.askmehelpdesk.com/showthread.php?t=512021)

  • Sep 29, 2010, 09:34 AM
    mstelly
    factor 6x^4-18x^3 12x^2 completely
  • Sep 29, 2010, 09:47 AM
    ebaines

    Yo're missing a sign in front of the 12x^2 term. I will assume it's supposed to be +12x^2.

    First thing to notice is that you can divide through by 6x^2, which greatly simplifies the problem:

    6x^2(x^2 - 3x + 2)

    Can you take it from here?

  • All times are GMT -7. The time now is 01:39 PM.