The second of three numbers is 4 times the first number. The third number is 12 less than the first. Find the three numbers given that there sum is 42

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Let the three numbers be A, B and C in this order.

You are told that B is 4 times A. That is B = 4A
Then C is less than A by 12. So, C = A - 12
You are also told that their sum is 42. So, A + B + C = 42.

Can you solve for A, B and C now? :)

Quote:

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Originally Posted by Unknown008

Let the three numbers be A, B and C in this order.

You are told that B is 4 times A. That is B = 4A
Then C is less than A by 12. So, C = A - 12
You are also told that their sum is 42. So, A + B + C = 42.

Can you solve for A, B and C now? :)

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Wish I had your brain... I have no clue to that problem... Your good , my man.. good.:D