I need to find the pattern in order to find the last product without multiplying. Thanks

1) 7*(7+1) = 7*8 = 5,625
2) 4*(4+1) = 4*5 = 2,025
3) 9*(9+1) = 9*10 = 9,025
4) 6*(6+1) = 6*7 = 4,225

For this to work,the first digits must be equal and the addition of the two second digits must equal to 10.

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Originally Posted by ROLCAM

1) 7*(7+1) = 7*8 = 5,625
2) 4*(4+1) = 4*5 = 2,025
3) 9*(9+1) = 9*10 = 9,025
4) 6*(6+1) = 6*7 = 4,225

For this to work,the first digits must be equal and the addition of the two second digits must equal to 10.

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Thank you so much! Foxhouse

Given a number A5, where A is a single digit, when you square it the first digits of the answer are always equal to the A^2 + A, and the last two digits are always 25. So for example, for 35^2. we set A = 3, and the first digits of the answer are 3^2+3 = 12. So: 35^2 = 1225.