When .500 mole of sodium is produced according to the reaction 2NaN3->3Na+Na, how many moles of Nitrogen gas are also produced?
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When .500 mole of sodium is produced according to the reaction 2NaN3->3Na+Na, how many moles of Nitrogen gas are also produced?
Your equation is not good.
Is it:
Then, balance your equation to give:
From here, you know that when 3 moles of Na are produced, you also get 1 mole of nitrogen gas.
Use proportions to find the number of moles of Nitrogen gas produced when 0.5 moles of Na are produced.
3 moles Na -> 1 mole N2
1 mole Na -> 1/3 mole N2
0.5 mole Na -> ? Moles N2
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