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-   -   Current and Resistance (https://www.askmehelpdesk.com/showthread.php?t=484646)

  • Jul 1, 2010, 03:20 PM
    Lime25
    Current and Resistance
    A 50-watt lamp, a 20-watt, a 75 watt lamp, and a 100-watt lamp are connected in parallel to a 110-volt circuit. Calculate a) the current through each lamp; b) the resistance of each lamp; c) the total resistance of the circuit.

  • Jul 1, 2010, 03:42 PM
    KISS

    That's a neat problem. I like it.

    Do you have any idea how to solve it?
  • Jul 2, 2010, 10:45 AM
    Unknown008

    Do you know the formulae you need to know? For example, for the first part, you need

    When you know this, you should use the formula from Ohm's Law, and apply your knowledge of how the total resistance in a circuit is affected when the components are in parallel.
  • Jul 2, 2010, 07:12 PM
    Lime25
    Comment on Unknown008's post
    This is what I have so far..
    50 W/110V=.45A
    20W/110W=.18A
    75W/110V=.68A
    100W/110V=.91A

    For the second part
    110V/.45A=244 Ohms
    110V/.18A=611 Ohms
    110V/.68A=162 ohms
    110V/.91A=121 ohms

    Now for the third part I know I would set it up like this
    1/244 +
  • Jul 3, 2010, 06:02 AM
    Unknown008

    A slight detail I'd like to point out, is that when you use the rounded off numbers, you are losing the accuracy of your results. If you have a storage facility in your calculator, I advise that you use it.

    For the resistances, for example, if you take all the numbers, you get:

    1. 110/0.4545... = 242 ohms
    2. 110/0.1818... = 605 ohms
    3. 110/0.6818... = 161 ohms
    4. 110/0.9090... = 121 ohms

    Only the third one needed rounding off, but all the rest were exact resistances.

    Then, for finding the total resistance, I get:



    Then,

    to two sig fig.
  • Jul 3, 2010, 06:37 AM
    KISS

    The 0 is significant. Get in the habit of using it. So, 68 becomes 0.68. In certain classes, namely physics, I got points knocked off from that many of times.

    We also had to do all calculations paying attention to significant figures and error bars.

    See, the problem wasn't that hard.
  • Jul 3, 2010, 06:43 AM
    Unknown008

    And in case you wonder why I chose to use 2 significant figures for the last part, it's because the values you got are all to 2 significant figures. You just cannot get more accurate answers than the values you used at first, right? ;)
  • Jul 3, 2010, 08:10 AM
    Lime25
    But isn't the final part asking to find total resistance of a parallel circuit? So I thought I had to use the other equation
  • Jul 3, 2010, 09:20 AM
    Unknown008

    Yes, you have to use:



    And that is what I used. Oh, and avoid using the 'reply' button. There is limited space there, and I have to see the thread to know that you replied to me. This is a feature that should be removed... The admins of the site are still working on it.

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