Ask Me Help Desk - Help with algebraic fractions

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Help with algebraic fractions

Solve the equation:

2x-3 - 2x-1 = 1
x-3 2x+1

The 2x+1 is meant to be under the 2x-1

We won't do your homework for you, but I will give you a hint: multiply through by the prodiuct of the denominators:

$ \frac {2x-3} {x-3} - \frac {2x-1} {2x+ 1} = 1 $

$ \frac {(2x-3)(x-3)(2x+1)} {x-3} - \frac {(2x-1)(x-3)(2x+1)} {2x+ 1} = (2x-3)(2x-1) $

$ (2x-3)(2x+1) -(2x-1)(x-3) = (2x-3)(2x-1) $

Can you take it from here?

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