3x^2 + x - 1/2 =0

I just don't understand. I know I have to move the 1/2 to the right but how do I divide by 3?

Hi, you can easily divide by 3, don't be afraid to use fractions

Here is a useful walkthrough for completing the square http://www.purplemath.com/modules/sqrquad.htm

When completing the square, it helps to know the following formula. It expedites matters, rather than going through the steps.


a(x+(b/(2a)))^2+c-(b^2/(4a))


In your case, a=3, b=1, c=-1.2

Quote:

---

Originally Posted by Capuchin

Hi, you can easily divide by 3, don't be afraid to use fractions

---

:rolleyes: nice

Hi, I have one metod to tell you (if you are afraid of using fractions)

3x^2 + x - 1/2 =0
multiply the left and the right by 2 so that 1/2 gets eliminated
6x^2+2x-1=0
now just go with your usual method...