f(x)=[(x+∆x )+2/((x+∆x))]-[((x)+2/((x) )) ]
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f(x)=[(x+∆x )+2/((x+∆x))]-[((x)+2/((x) )) ]
Two items:
1. Why do you have so many parentheses in this equation? It looks like what you mean is this:
is that right?
2. Do you have a question?
You are right, to many parenthesis. Here is the correct the equation.
f(x)=[(x+∆x+2)/(x+∆x)]-[(x+2)/(x)]
OK great. That answers the first item I asked about. But how about the second - do you have a question?
Ok. My question is, what it would be the final result if I make the algebraic sustraction of the first function minus the second function.
First function: [(x+∆x+2)/(x+∆x)] MINUS (-) Second function: [(x+2)/(x)]
I get:
which for small values ofapproaches:
Ok, great. And for the following one:
First function: [(x+∆x)+(2/(x+∆x))] MINUS (-) Second function: [x+(2/x)]
Thanks.
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