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-   -   Algebraic Sum (https://www.askmehelpdesk.com/showthread.php?t=466188)

  • Apr 21, 2010, 01:29 PM
    Alejandro Sanchez
    Algebraic Sum
    f(x)=[(x+∆x )+2/((x+∆x))]-[((x)+2/((x) )) ]
  • Apr 21, 2010, 02:29 PM
    ebaines

    Two items:

    1. Why do you have so many parentheses in this equation? It looks like what you mean is this:



    is that right?

    2. Do you have a question?
  • Apr 21, 2010, 02:41 PM
    Alejandro Sanchez
    You are right, to many parenthesis. Here is the correct the equation.

    f(x)=[(x+∆x+2)/(x+∆x)]-[(x+2)/(x)]
  • Apr 21, 2010, 02:46 PM
    ebaines

    OK great. That answers the first item I asked about. But how about the second - do you have a question?
  • Apr 21, 2010, 02:51 PM
    Alejandro Sanchez
    Ok. My question is, what it would be the final result if I make the algebraic sustraction of the first function minus the second function.

    First function: [(x+∆x+2)/(x+∆x)] MINUS (-) Second function: [(x+2)/(x)]
  • Apr 21, 2010, 03:06 PM
    ebaines

    I get:



    which for small values of approaches:

  • Apr 21, 2010, 03:16 PM
    Alejandro Sanchez
    Ok, great. And for the following one:

    First function: [(x+∆x)+(2/(x+∆x))] MINUS (-) Second function: [x+(2/x)]
  • Apr 21, 2010, 03:42 PM
    Alejandro Sanchez
    Thanks.

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