what's the answer to this problem 4 1/3 x 4 1/4 1/3 and 1/4 are exponents

your problem is: 4^(1/3)x4^(1/4)

multiplying two numbers with the same base but different exponents is done by adding the exponents
x^a*x^b=x^(a+b)

for example:
2^3*2^4=2^(3+4)=2^7=128

hope this helps!

4^(1/3) + 4^(1/4) = 4^((1/3) +1/4)) = 4^(7/12) = (2^2)^7/12) =2^(2*(7/12)) = 2^(7/6)

How do you add or sub fractions in alegebra with diff denominators

This should be a new question. However, just like with normal numbers you need to get to a common denominator. For example,

juhi2011, if you think my answer is wrong please provide the right answer to prove that you are correct so that I may have a chance to disagree with you.

Quote:

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Originally Posted by asterisk_man

your problem is: 4^(1/3)x4^(1/4)

multiplying two numbers with the same base but different exponents is done by adding the exponents
x^a*x^b=x^(a+b)

for example:
2^3*2^4=2^(3+4)=2^7=128

hope this helps!

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Hey don't stir your nerve.. be cool and read this..
Up to the statement which you have written is correct ..."multiplying two numbers with the same base but different exponents is done by adding the exponents
x^a*x^b=x^(a+b)" but after that the powers are a fraction that is 1/3 and 1/4 but you have added 3 and 4. even if you are changing the base as to the powers become 2/3 and 2/4... do you agree or disagree now??

I couldn't disagree more.
My example did not use fractional exponents.
Do you disagree that 2^3*2^4=128?
Do you disagree with the identity x^a*x^b=x^(a+b)?
I gave an example of how to multiply two numbers with the same base but different exponents. I assumed that the original poster was advanced enough to know how to add fractions.
Unless you can point to something that is incorrect with my answer I would appreciate it if you'd admit your mistake and be more conservative with your negative ratings in the future.