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-   -   How do you solve 3x 7y=-1 2x+3y=6 in the substitution method (https://www.askmehelpdesk.com/showthread.php?t=454491)

  • Mar 4, 2010, 07:53 PM
    DOAalex
    How do you solve 3x 7y=-1 2x+3y=6 in the substitution method
    I have tried the addition method on this problem where I multiple both equations if the constant but my teacher swears there is another better way so please help me
  • Mar 4, 2010, 08:30 PM
    ROLCAM

    3x + 7y= -1
    2x + 3y= 6
    _______________
    6X + 14Y = -2
    -6X - 9Y = -18
    ________________

    5Y = -20
    Y = -4
    ________________
    2x + 3y = 6
    2X -12 = 6
    2X = 6+12
    2X = 18
    X =9

    _______________________

    X=9
    Y = -4
    ___________________________
    proof:-

    3x + 7y= -1 ****27-28 = -1
    2x + 3y= 6 *****18-12 = 6
  • Mar 4, 2010, 09:32 PM
    KISS

    You need to solve one of the equations for x or y and substitute into the other one. It will be a little messy. Fractions.
  • Mar 5, 2010, 12:44 PM
    Unknown008

    Well, strictly speaking, yes, using substitution will give rise to fractions, making it a little messy.

    You can try substituting something else instead of x or y to make is easier.

    3x + 7y= -1
    2x + 3y= 6

    Multiply (I) by 2 and (ii) by 3.

    6x + 14y= -2
    6x + 9y= 24

    Make 6x the subject of formula in the first equation.

    6x = -2 - 14y

    Now, substitute 6x by (-2 -14y) into the other equation, giving:

    (-2 - 14y) + 9y= 24

    You substituted 6x instead of x. Now it's easier.
  • Mar 5, 2010, 01:59 PM
    KISS

    Why didn't I think of that? (Can't spread rep).
  • Mar 6, 2010, 08:21 AM
    Unknown008

    Don't worry :) This happens to me as well.

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