Ask Me Help Desk - Find the magnitude of the position vector (-'5,'11)

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Find the magnitude of the position vector (-√5,√11)

Find the magnitude of the position vector (-√5,√11)

The magnitude is given by:

$\sqrt{x^2 + y^2}$

just like the Pythagoras' theorem.

x is $-\sqrt5$ and y is $\sqrt{11}$

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