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-   -   A six -sided cubed (https://www.askmehelpdesk.com/showthread.php?t=439595)

  • Jan 26, 2010, 07:04 PM
    anette19
    a six -sided cubed
    a six-sided cube is rolled. Find the probability of P(4)
  • Jan 26, 2010, 07:10 PM
    Alty

    You find it, post the equation and your work and then we'll go from there.

    We will not do your homework for you. It's your homework, not ours.
  • Jan 26, 2010, 07:56 PM
    EmoPrincess

    Think of it the same way as your marble problem. The part divided by the whole. What is your part in this problem? What is your whole?

    *remember- in a problem with dice or spinners, the values "printed" are not the values used.
  • Jan 26, 2010, 08:52 PM
    anette19
    1/5
  • Jan 26, 2010, 09:11 PM
    EmoPrincess

    How did you come to that answer
  • Jan 27, 2010, 10:41 AM
    Unknown008

    The probability of an event is not always 1/5. That's the second post where you say the same thing.

    Here, there are only 6 possible outcomes. The probability of having any number is therefore 1/6 (one possibility out of 6).

    What do you think is the answer?
  • Jan 27, 2010, 09:06 PM
    morgaine300

    Actually, this is much like this one about a card:
    https://www.askmehelpdesk.com/math-s...ty-439583.html

    Unlike the marble one, this is asking for only one outcome, a 4. The marble one was asking for the probability of different outcomes, more than one outcome. When you're looking for more than one (like 3 OR 4), then you add them. But the individual probabilities (JUST 4) always comes from doing the same thing:

    As someone already said, the probably is the number of ways to get the "favorable" outcome (the one you're looking for), divided by the number of total possible outcomes. As Unky said, it's not just automatically 1/5 just because it's "similar" to something else. You have to think about what each of those numbers are. Instead of continually posting all your homework problems, learn HOW to solve this type of problem and apply it to your other problems.

    How many ways are there to get a 4?

    How many possible outcomes are there if you roll the die? Not just the one you want (4), but any possible outcome?

    Then divide them.

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