I need to know what is the capacity of the electrical transformer that I need to put to work 8 semi automatic welding machines of 600 amps

1 kv is 1000 amps so 8 at 600 amps..
That's 4800 amps which is 4.8 kva you will probably have to get a 5 or a 7 whichever is the next available size!

Light bulb:

Is that a primary or secondary requirement. 8 machines at 600/8 amps (work side) makes sense. We don't know what voltage on the secondary side.

Your welder should have power requirements on the primary side.

If its 50A # 240 V = 200 A at x volts;

You effecively have a ratio of 50A/200A * (I required @ 240)/(I needed at machine)

I needed at machine is 600/8 on the work side?

This is an example. The problem didn't make sense.

Transformers are typically sized up. I would contact the mfr for power factor information.

Am I right?

Quote:

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Originally Posted by KeepItSimpleStupid

Light bulb:

Is that a primary or secondary requirement. 8 machines at 600/8 amps (work side) makes sense. We don't know what voltage on the secondary side.

Your welder should have power requirements on the primary side.

If its 50A # 240 V = 200 A at x volts;

You effecively have a ratio of 50A/200A * (I required @ 240)/(I needed at machine)

I needed at machine is 600/8 on the work side?

This is an example. The problem didn't make sense.

Transformers are typically sized up. I would contact the mfr for power factor information.

Am I right?

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I am not following what you are saying I mean the primary and secondary thing have nothing to do with the kva the question was geared toward the kva not the voltage of the primary side.. I mean if his line votage is 600 and he goes down to 480 that's a given its now a matter of amp draw on the tranfomer is the way I always understood it maybe mr russell can shed some light on the subject for us?

I've welded. Take a look at this welder. It's no so simple.

Invertec V205-T DC: Lincoln Electric Item #: K2629-1 - WeldingMart.com

It's also a 115/230 V auto switching welder with a 6-200 A output.

Duty cycle matters for welders. You need to know:

1. The input voltage
2. The current at that input voltage for 75 A out (from 600/8)
3. Duty cycle spec

4. We need the output at the tool reflected back to the input current.

How can you multiply Amps with an unknown volts to get kVA? It's impossible. It's just kVA= x*600