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-   -   Neutralization of Calcium Hydroxide by hydrochloric acid (https://www.askmehelpdesk.com/showthread.php?t=424001)

  • Dec 10, 2009, 08:55 PM
    igob8a
    Neutralization of Calcium Hydroxide by hydrochloric acid
    Hi there, I have a question about the reaction:
    Ca(OH)2(s) + 2HCl(l) ⇌ CaCl2(aq) + 2H2O(l)

    1. If 10.02mL of 0.100mol/L hydrochloric acid is required to neutralize 25.00mL of a saturated calcium hydroxide solution, what is the concentration of the hydroxide ions present?

    2. What is the solubility of calcium hydroxide in mol/L?

    I got the concentration to be 0.02004mol/L using C1V1=C2V2, but I can't figure out how to go about solving the second question. :confused:

    Thanks in advance! :)
  • Dec 11, 2009, 10:26 PM
    InfoJunkie4Life

    Quote:

    Ca(OH)2(s) + 2HCl(l) ⇌ CaCl2(aq) + 2H2O(l)

    1. If 10.02mL of 0.100mol/L hydrochloric acid is required to neutralize 25.00mL of a saturated calcium hydroxide solution, what is the concentration of the hydroxide ions present?

    2. What is the solubility of calcium hydroxide in mol/L?
    You for got that it is asking for the concentration of OH ions. There are 2 moles of OH in a 1mol/L Ca(OH)2 solution.. Which means the concentration of OH ions should be twice as much as the concentration of the Ca ions or even the Ca(OH)2 solution.

    Secondly, your number 0.02004mol/L is the concentration of saturated Ca(OH)2. According to question one, that is a saturated solution, which happens to be the answer to question 2. The saturation solution of a compound represents the amount of that compound that can be dissolved in water. Which is the same definition as solubility.

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