Ask Me Help Desk - Find a vertex of parabola with only yint and a point.

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find a vertex of parabola with only yint and a point.

I'm given the vertex: (x,6.17)
y-Int: (0,5)
One x-int: (10.42, 0)

How do I find the rest of the vertex, and then find the equation for the parabola.

Quote:

Originally Posted by nmstar56

I'm given the vertex: (x,6.17)
y-Int: (0,5)
One x-int: (10.42, 0)

How do I find the rest of the vertex, and then find the equation for the parabola.

There are various ways to appproach this, but you could use

$y=a(x-h)^{2}+k$

Where h and k are the vertex coordinates. Plug in your knowns and solve for h and a.

$0=a(10.42-h)^{2}+6.17$

$5=a(0-h)^{2}+6.17$

Solve for a and h.

Thanks, Unknown. You thought it was nice, but the poster must've have thought so because they never responded back.

That's how most of them are, look for an answer, never to look if they got an answer or not. I'm sure most of them think they'll get the answer a second after they post their question :rolleyes:

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