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-   -   Balancing a chemical equation (https://www.askmehelpdesk.com/showthread.php?t=419809)

  • Nov 27, 2009, 12:03 PM
    Hudsonleaf
    Balancing a chemical equation
    I am trying to Balance this Equation and having troubles.

    I am supposed to put the co efficients in the spaces.

    ___MgF2 + Li2CO3=___MgCO3+___LiF


    Here is also another one that I did but want to make sure I did it right?

    ___LiCl+___Br2=___LiBr+___Cl2

    THANKS FOR YOUR HELP AHEAD OF TIME!! Very much appreciation~~~
  • Nov 27, 2009, 07:17 PM
    InfoJunkie4Life
    The object is to have the same amount of the same types of atoms on both side of the equations.

  • Nov 27, 2009, 07:22 PM
    InfoJunkie4Life

  • Nov 28, 2009, 04:29 PM
    mathwiz3502

    My teacher has us make a t chart with the number of atoms on each side, then we add coefficients and cross out and calculate the new number of atoms until they are equal.
  • Nov 28, 2009, 10:43 PM
    InfoJunkie4Life

    Excellent method, but I do most of it in my head. I've been working with these types of equations for years.
  • Nov 29, 2009, 05:24 AM
    mathwiz3502

    So do I but some of the brightest students have to use this method.
  • Nov 29, 2009, 09:28 AM
    InfoJunkie4Life

    Oh, I understand.
  • Nov 29, 2009, 12:37 PM
    Hudsonleaf

    So what should go in the four spaces in order should be

    2, 1, 2, 1 ?
  • Nov 29, 2009, 12:44 PM
    Hudsonleaf
    Here is one more, I would like to know if I did this one right also?

    ___PbBr2 +___ HCl=___HBr+___PbCl2

    1 2 2 2??
  • Nov 29, 2009, 06:27 PM
    Perito



    Almost, but it's not quite right. You have one lead atom on the left and two chlorine atoms on the left. On the right, you have two lead atoms and four chlorine atoms.
  • Nov 30, 2009, 07:02 PM
    mathwiz3502
    [math]1PbBr_2+HCl/rightarrow2HBr+1PbCl_2
  • Nov 30, 2009, 07:03 PM
    mathwiz3502
    Sorry,
  • Nov 30, 2009, 07:06 PM
    mathwiz3502
    1221
  • Dec 1, 2009, 07:03 AM
    Unknown008
    Quote:

    Originally Posted by Hudsonleaf View Post
    Here is one more, I would like to know if I did this one right also?

    ___PbBr2 +___ HCl=___HBr+___PbCl2

    1 2 2 2????????????????

    Ok, in your head, look at Pb first. There's one on both sides, so good.
    Then, you see Br, there are two of them on the left and only one on the right. That means that you have to put '2' in from of HBr.

    Doing so doubles the H. Since there's only one on the left hand side, double the HCl. That means you also have 2 Cl, but you already have 2 Cl on the left!

    Ok, you saw everything. Time to check.
    1 Pb on each side. Good
    2 Br on each side. Good
    2 H on each side. Good
    2 Cl on each side. Good.

    That's how I do, a sort of 'chaining' with the elements I'm dealing with, trying to fix one as soon as possible. That works for the easy equations. Other, more difficult require perseverance, and sometimes the use of half equations and fractions.

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