A stone is thrown from a bridge with a initial vertical velocity of magnitude 4.0m/s. Determine the stone's velocity after 2.2s if the direction of the initial velocity is
a) upward
b)down ward
Neglect air resistance
>?
How can I do this question
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A stone is thrown from a bridge with a initial vertical velocity of magnitude 4.0m/s. Determine the stone's velocity after 2.2s if the direction of the initial velocity is
a) upward
b)down ward
Neglect air resistance
>?
How can I do this question
use vf=vi+gt for downward
The formula is: v = u + at
Where: v = final velocity, u = initial velocity, a = acceleration
If thrown upward, acceleration = -g
If thrown downward, acceleration = g
use the formular v = u + at, where a is represented by g, being the force of gravity. A = -g if stone is thrown upwards and a = g when stone is thrown downwars. Hence for (a) formular is v = u - gt
and for (b) v = u + gt.
These equations are vector equations. You can use any direction, but put components in the same directions
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