x to the 3rd-9x squared-8x-4/x+3=

Is that it?

Well here you go. I'll proceed with long division:
1. Divide x^3 by x and put the answer up there
2. Take the value you just obtained and multiply that by (x+3), putting the result below your numerator.
3. Subtract that result from your numerator.
4. Repeat with the next term.

Code:

---

iiiiiiiix^2 - 12x  + 28   
x + 3 | x^3 - 9x^2 - 8x - 4
        x^3 + 3x^2
          0 -12x^2 - 8x - 4
            12x^2 -36x - 4
                0 +28x - 4
                    28x + 84
                      0 - 88

---

So, your answer is x^2 + 12x + 28 with a remainder of -88.

I hope it helped! :)

Don't forget Unknown008 that with a remainder the answer is actually x^2+12x+28+(x+3)
(over -88)

(x+3)
(-88)

Actually, it's and not

Because:


Dividing everything by (x+3) gives:

Sorry

Hey unky:

Why don't you teach mathwiz and us all how to write like that.

A sticky or a link.

You can show the tags using the noparse attribute.

e.g. [b]This in bold[/b] is the Vbulletin code for This in bold

Maybe you can create a sticky someplace like "Forum Help" or the "math & Science section" Just a thought.

That's already there KISS, RickJ was the one who 'taught' me how to do so :). Check the sticky in the math-sciences page.