Determine the number of mL of .03 M phosphoric acid required to neutralize 25.00 mL of .015 M calcium hydroxide. Balanced equation = 3Ca(OH)2 + 2H3PO4 ---> Ca3(PO4)2 + 6H2O

1. Find the number of moles of Ca(OH)2.
2. Use your balanced equation to find the mole ratio of Ca(OH)2 and H3PO4.
3. From the ratio, find the amount of moles of H3PO4 which reacts.
4. Using the concentration and amount of moles the volume becomes easy.

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.025L * .015 mol Ca(OH)2= 3.75 * 10^-4 mole Ca(OH)2

3.75 * 10^-4 * (2/3) = 2.5 * 10^-4 mole H3PO4

2.5 * 10^-4/.03= .08333 L * 1000 = 8.33 mL

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Right! It's perfect! :)

You're welcome! :)