Three towns A, B and C are connected by straight roads. B is due west of A, C is due south of B and the bearing of C from A is 220 degrees. If the distance from A to B is 300 km:
a) find the distance from A to C
b) find the bearing from A to C
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Three towns A, B and C are connected by straight roads. B is due west of A, C is due south of B and the bearing of C from A is 220 degrees. If the distance from A to B is 300 km:
a) find the distance from A to C
b) find the bearing from A to C
Based on what you have given, the distance between A and C is 466.7 km, and the bearing from A to C is 220 deg. The bearing from C to A is the reciprocal, 40 deg.
(Edited)
Sorry, but the distance is not good.
The easiest way to do it is by having a sketch in front of you.
Attachment 26502
You can find angle BAC by having 270 - 220 = 50 degrees
Using cos, you know that
Solving for AC will give you 466.7 m.
Then, the bearing is indeed 40 degrees
It's OK, it might have happened to anybody including myself :)Quote:
Originally Posted by jmjoseph
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