write a balanced reaction between Ba(OH)2 and H2SO4.
----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

explain the observed changes in conductivity.
----> H2SO4-strong conductivity. Ba(OH)2-weak conductivity.

Please check these answers are correct or not , if not please explain for me

Thanks

Well, at first you had Ba(SO4)2 and H2SO4 which are both electrolytes. Then, you have BaSO4 which is a solid, insoluble in water. A solid does not conduct electricity, nor does pure water. So, conductivity decreases.

write a balanced reaction between Ba(OH)2 and H2SO4.
----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

So, this equation is correct?


Thanks for your explain

Yup, you can self check it. Count the number of Ba, H, S, O on the right and then on the left. You'll see they are equal in number.

Yes its perfectly balanced!

Thanks

You're welcome :)

reaction is
Ba(OH)2 + H2SO4 ====> BaSO4 + 2H2O
it is a balane equation and coductivity is depand upon capacity to dissociate in to ions. An BaSO4 have less capabilty to produce ions than H2SO4 and Ba(OH)4