You are a buyer bidding sight unseen on a lot of 10,000 uncut diamonds. You are able to take a random sample of 100 stones from the lot. You determine that the mean weight of the sample is 1.52 ct with a standard deviation of 0.11 ct. Before making a bid, you need to estimate the percentage of the stones which will yield a finished or cut diamond of MORE than 1.00 ct. You know that on average, the cutting and finishing process yields a stone with 2/3 the weight of the uncut raw material. Based on this information, what would you estimate the number of stones yielding a finished diamond of MORE than 1.00 ct to be?
[I] think the answer is 5720. The stdv is small .11 and more would be to the right of the bell curve but this is just looking at the question not proving it mathematically?