Is this right?

h(x) = 3e^sin(x + 2)

h'(x) = 3e^sin(x + 2) X cos(x+2)(1)

Quote:

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Originally Posted by ankara55t

Is this right?

h(x) = 3e^sin(x + 2)

h'(x) = 3e^sin(x + 2) X cos(x+2)(1)

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Yep, that's it. Very good. You'd get a greenie if I could give you one. :)

Except, try using LaTex if you plan on frequenting this math site on a regular basis.

Like so:

To see the code I typed to make it display that way, just click on 'quote user'.