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-   -   Factoring 4x^2 8x (https://www.askmehelpdesk.com/showthread.php?t=407069)

  • Oct 17, 2009, 04:54 PM
    KingJimXXIV
    Factoring 4x^2 – 8x
    I'm supposed to factor 4x^2 – 8x... it's a multiple choice question and I can't decide between three of the answers... my first thought was 2x(2x-4) but the other choices are x(4x-8) or 4x(x-2)... the only other answer choice is 4(x^2-2)... I thought I knew what I was doing but I guess not... and the example in the book isn't helping... could someone please tell me how to solve this
  • Oct 17, 2009, 05:38 PM
    galactus
    Just factor out the smallest of each. You have an x and an x^2, a 4 and an 8. Factor out the 4 and x.
  • Oct 17, 2009, 10:06 PM
    Nhatkiem

    write out the factors.

    4x^2 -8x
    (2*2)(x*x)-(2*2*2*x)

    Here we see two terms, the factors these terms have in common are: 2 factors of 2, and 1 factor of x

    (2*2)(x*x)-(2*2*2)(x)

    When we pull these factors out, we essentially divide the two terms by those factors!

    [2*2*x](x-2)
  • Oct 17, 2009, 10:07 PM
    Nhatkiem
    Forgot to add, of course you would simplify the terms to:

    4x(x-2)

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