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-   -   Probability of 20ml of rainfall when 13ml chance is 87.7% and 16.9ml chance is 40.9% (https://www.askmehelpdesk.com/showthread.php?t=405958)

  • Oct 14, 2009, 12:06 PM
    knthurima
    Probability of 20ml of rainfall when 13ml chance is 87.7% and 16.9ml chance is 40.9%
    Farmers in District D know when to plant and harvest because rainfall follows a particular pattern which repeats itself every seven months. Weather records for this particular area indicate a normal distribution as far as rainfall is concerned. The records further reveal that the chances of at least 13.4 millimeters of rainfall have remained at 87.7%, while the chances of at most 16.9 millimeters remain at 40.9%. For the farmers to plant wheat they need at least 20 millimeters of rainfall, with what probability do they plant the wheat?? :confused: SHOW ME HOW TO WORK THIS OUT! THANK YOU!
  • Oct 15, 2009, 05:06 AM
    ROLCAM

    This works out as follows:-
    (by extrapolation in reverse).
    (based on the heading details which varies from the details in the bulk of the question)

    Number

    1 13.0 87.7
    2 13.1 86.5
    3 13.2 85.3
    4 13.3 84.1
    5 13.4 82.9
    6 13.5 81.7
    7 13.6 80.5
    8 13.7 79.3
    9 13.8 78.1
    10 13.9 76.9
    11 14.0 75.7
    12 14.1 74.5
    13 14.2 73.3
    14 14.3 72.1
    15 14.4 70.9
    16 14.5 69.7
    17 14.6 68.5
    18 14.7 67.3
    19 14.8 66.1
    20 14.9 64.9
    21 15.0 63.7
    22 15.1 62.5
    23 15.2 61.3
    24 15.3 60.1
    25 15.4 58.9
    26 15.5 57.7
    27 15.6 56.5
    28 15.7 55.3
    29 15.8 54.1
    30 15.9 52.9
    31 16.0 51.7
    32 16.1 50.5
    33 16.2 49.3
    34 16.3 48.1
    35 16.4 46.9
    36 16.5 45.7
    37 16.6 44.5
    38 16.7 43.3
    39 16.8 42.1
    40 16.9 40.9
    41 17.0 39.7
    42 17.1 38.5
    43 17.2 37.3
    44 17.3 36.1
    45 17.4 34.9
    46 17.5 33.7
    47 17.6 32.5
    48 17.7 31.3
    49 17.8 30.1
    50 17.9 28.9
    51 18.0 27.7
    52 18.1 26.5
    53 18.2 25.3
    54 18.3 24.1
    55 18.4 22.9
    56 18.5 21.7
    57 18.6 20.5
    58 18.7 19.3
    59 18.8 18.1
    60 18.9 16.9
    61 19.0 15.7
    62 19.1 14.5
    63 19.2 13.3
    64 19.3 12.1
    65 19.4 10.9
    66 19.5 9.7
    67 19.6 8.5
    68 19.7 7.3
    69 19.8 6.1
    70 19.9 4.9
    71 20.0 3.7

    Conclusion a 20 millimeters has a 3.7%
    probability.
  • Oct 15, 2009, 08:20 AM
    Chris-infj

    Let X be the amount of rainfall in mm

    It is given that X follows a normal distribution. What is not known is the mean and the standard deviation of rainfall.

    You're given = 0.877.

    1. Draw a bell-shaped curve and illustrate that.

    2. Then look up in a standard normal table and find the z value that corresponds to a p value of 0.877.

    3. Is it a positive z or a negative value? You'll know when you look at your drawing. In fact, it is strongly advised to draw a picture.

    4. So then you use the formula to obtain a first equation involving and .

    Repeat as from step 1. for the other piece of information = 0.409.

    Draw a picture for that too. Look up the z value corresponding to a p value of 0.409 in normal tables or use Excel Norminv function.

    You should get two simultaneous equations with and as two unknowns and solve to get them.

    Then armed with these values, you can calculate .
  • Oct 15, 2009, 11:15 AM
    Unknown008

    Do we do these in the S2 paper?
  • Oct 16, 2009, 07:07 AM
    Chris-infj
    Quote:

    Originally Posted by Unknown008 View Post
    Do we do these in the S2 paper?

    S1 paper
  • Oct 17, 2009, 08:15 AM
    Unknown008

    Ok...

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