Solve for x in the below algebraic equation
3^2x + 19 = 10^x
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Solve for x in the below algebraic equation
3^2x + 19 = 10^x
Sorry :o I'll give it a try later on... I did a very big mistake
EDIT: Ok, now I'll do it.
The only way that I see, is that you have to solve this by graphing, or iterations, if you know how to do it.
Draw the graph ofand
.
Look for the point of intersection, and check it's x coordinate, which is the solution to your answer.
I was trying the iteration, and was looking for the point where the sign changes, and found that x = 2 solved the equation...
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