How do you solve this problem?
3^2x+ 3^x -12 = 0
and can you do the steps for me to also please.
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How do you solve this problem?
3^2x+ 3^x -12 = 0
and can you do the steps for me to also please.
It's fairly simple as soon as you realize you can factor it.Quote:
How do you solve this problem?
3^2x+ 3^x -12 = 0
I wish I could (actually, I don't -- but I'm lazy). Just create two equations from the above equation. Move the constant to the right in each equation and take the logarithm of both sides.Quote:
and can you do the steps for me to also please.
Okay, the easiest way to do this is by a simple substitution.
Let
Then,
Now, you can solve it like any other quadratic;
Then,
y = -4or
y = 3
Replace y by 3^x
Since 3^x cannot be negative, it must be the other one.
So, x = 1
:)
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