How would you solve this problem:

3^ radical 4 times 3^ radical 16

(If that even makes sense)

I REALLY could use some help on algebra 2! Thankx

You would simplify it into: from the square root of 4 times the squre root of 16, first you would do square root of 4 which is 2 and then the square root of 16 which is 4.
So that leaves you with 2 times 4 which is 8. :)

(I think that was your question because I didn't understand what the "3^" meant)

Hope that helps. :D

3^[radical symbol]4=9
3^[radical symbol]16=81
9x81=729


-chainer (I was just walking by, saw comp, and decided to put my answer)

rewrite it as:

3^2 * 3^4

add the exponents:

3^6

simplify:

729