I have to solve this linear equation with 3 variabes:
x-2y=1
x+3y+z=0
2x-2z=18
answer has to be in (x,y,z) formation... please help
![]() |
I have to solve this linear equation with 3 variabes:
x-2y=1
x+3y+z=0
2x-2z=18
answer has to be in (x,y,z) formation... please help
Use elimination method or substitution method. Here is elimination:
Multiply the second row by 2:
Now, add it to the third row:
That eliminated z.
Now, Multiply the first row by -4:
Add to the second row:
Now, back substitute to find x and z.
All times are GMT -7. The time now is 11:40 AM. |