Hi, can someone please tell me what the formula for solving "a" will be.
Thanks
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Hi, can someone please tell me what the formula for solving "a" will be.
Thanks
A squared + B squared = C squared
Thank you, but I'm crippled at maths so if its possible could you explain how you get the answer?
Spend a little time getting familiar with the Pythagorean Theorem... plenty of info on PT all over the 'net.
You'll find ol' Pythag to be a good friend you'll call on frequently, and with respect to your triangle, he tells you that
And from there you can easily solve for a.
Much obliged, Unk8! But it's really just a matter of looking at the problem from the...
... right angle :o (Sorry, couldn't resist)
Hey, a good answer is worth a greenie. :) And that's not against the rules, on the contrary, that's what the rules say:
Ask Me Help Desk - FAQ: <u>Additional features used with posting questions and answers</u>Quote:
Originally Posted by RULES
Jean:
I thin everyone gave you a bad rap. When two sides of a right triangle are known, the pythagorean theorem can be used to solve it.
We may know this as a^2 + B^2 = c^2 or
better yet:
a^2 + b^2 = h^2
where h is the hypotenuse or the longest side. The hypenuse is also the side across from the right angle.
While we are at it:
Oscar had a headache over algebra
and also remember sine, cosine and tangent
So from Oscar Had we get O/H = sine theta
and A/H we get ajacent/hypotenuse = cos theta
and O/A we get Opposite/Hypotenuse or Tangent theta
All the sine theta = O/H says is that the opposite side divided by the adjacent side of the angle between them are related by the ratio equal to the sine of the angle.
Just be careful with radians and degrees. If when using a calculator, you can always check say the sin (2*PI) and if you get something near zero it's in radians mode and not degrees.
Whether anyone gave Jean a bad rap or not depends on the level of the class. I can solve this but have no idea what you're talking about.
There must be a full moon today.
Oscar had a headache over algebra is a way of memorizing the definitions of sine, cosine and tangent.
2 * PI radians = 360 degrees. PI = 3.1415926...
Which isn't really related to the problem at hand, but probably will be in the near future.
I've got one;
SOH CAH TOA
Sin = Opp / Hyp
Cos = Adj / Hyp
Tan = Opp / Adj
That's how I used to recall my simple trig. :)
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