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-   -   Substitution and Elimination (https://www.askmehelpdesk.com/showthread.php?t=386261)

  • Aug 12, 2009, 03:58 PM
    usaboy94
    Substitution and Elimination
    Y=2X+3
    Y=4X+4 Solve by substitution or elimination. I need step by step.
  • Aug 12, 2009, 04:22 PM
    HelpinHere

    Solve by substitution or elimination.


    Substitution:
    Solve for any of the variables in any of the equations.
    Replace that variable with its value in the unused equation.
    Simplify the equation
    Solve for the unknowns.

    Elimination:
    Decide which variable you are going to eliminate.
    Use your knowledge of fractions to make the coeffecients for that variable the same number, but opposites. (one +, one -)
    Add the two equations. One of the variables should disappear.
    Solve for the remaining variable.
    Solve for the other variable using either equation.

    Examples:



    Sub:















    Elim:











    Now, you just do the same thing, but using your equations.
    If you get stuck, post what you have gotten, and I'll help you from there.

    (Please, someone correct me if I'm wrong.)
  • Aug 12, 2009, 04:42 PM
    KISS

    Elimination:
    Reverse eqns

    Y=4X+4
    Y=2X+3

    subtract each term

    0Y=2x+1 ------> Go from there
  • Aug 12, 2009, 04:46 PM
    HelpinHere
    Quote:

    Originally Posted by KeepItSimpleStupid View Post
    Elimination:
    Reverse eqns
    substract each term
    Go from there

    Huh? Am I missing something? And... ooh, I see what you did there...
    You did it the EASY way, :p
  • Aug 12, 2009, 04:47 PM
    usaboy94
    Quote:

    Originally Posted by KeepItSimpleStupid View Post
    Elimination:
    Reverse eqns

    Y=4X+4
    Y=2X+3

    substract each term

    0Y=2x+1 ------> Go from there

    Thanks
  • Aug 12, 2009, 05:29 PM
    KISS
    Your right, the step that wasn't needed is to multiply one of the Multiply eqns by to make it easy to add or subtract.

    Example:

    y=4x+4 (1)
    10y=5x+3

    Multiply to eqn 1 by 10 or fractions, etc.

    10y=40x+40 (1)
    10y=5x+3

    Now subtract

    Eqn #1 is still the same when multiplied by a constant

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