Advanced Functions: Solving Logs
Hey guys,
I took a year off and now I'm back in the books.
Now it might be because I've been doing nothing but math today and my brain is fried, but I can't figure out these two problems. Any help is greatly appreciated!
Solve for the variable:
a) logy81=4/3
so I've rewritten it as:
y^4/3= 81
y=?
and that's where I'm at. I have no clue what the base of y is or how to find it.
b)log8 Y=2/3
8^2/3=y
y=?
How am I suppose to write the value for y leave it as 8^2/3?
I hope that wasn't to confusing but thanks for taking a look.
Trevor