Solve each equation for principle angle values (where reasonable) or principle
angle inverse trigonometric functions at the proper point
1.2cosē(x)+cos(x)-1=0
2.sin(3x)=cos(3x)
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Solve each equation for principle angle values (where reasonable) or principle
angle inverse trigonometric functions at the proper point
1.2cosē(x)+cos(x)-1=0
2.sin(3x)=cos(3x)
1. This is solved just like an ordinary equation. Try a simple substitution, Y = cos(x).Quote:
Solve each equation for principle angle values (where reasonable) or principle
angle inverse trigonometric functions at the proper point
1.2cosē(x)+cos(x)-1=0
2.sin(3x)=cos(3x)
becomes
You can solve this using the quadratic equation:
And substitute back into the equation
Then
2.
thank you so much...
I did 2nd one like this
sin3(0)=cos3(0)
tan3(0)=1
3(0)=45 degrees
0 = 15 degrees
am I right?
This doesn't look like the second one you gave me. You had written "sin(3x)", including the parentheses. Now you're writing Sin3(0). Where did the "0" come from and is thisQuote:
i did 2nd one like this
sin3(0)=cos3(0)
tan3(0)=1
3(0)=45 degrees
0 = 15 degrees
am i right?
or is it
? I'll assume the "0" is a typo and that the 3 comes inside the parentheses:
Then you are correct.
LOL! I reckon the OP mean theta
Some of these things zoom over my head.
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