How do I answer this question :eek:... "if a computer had a 12-bit address bus, how many different memory locations could it address directly?"... thanks :D:D

Smells like homework. So...

A 1 bit bus could address locations:
0
1
or 2^1 = 2 locations.

A 2 bit bus could address locations:
00
01
10
11
or 2^2 = 4 locations.

A 3 bit bus could address locations:
000
001
010
011
100
101
110
111
or 2^3 = 8 locations

See a pattern?

yeah , its doubling? :D
so a 4 bit bus could address locations :
0000
0100
0110
0111
0001
0011
0100
0010
1111
1110
1100
1000
1011
1001
1010
1101
= 16 :D

It's 2^(Number'o'Bits).

Whaaat? So is the answer I got not right ?

No it's right, I just giving general formula for any given number of bits.

Oh thanks :)