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Unit Conversion

How to convert enthalpy of fusion (delta H) with units in kJ/mol to J/mm3?

I have a paper which says that enthalpy of fusion of copper (13.01 kJ/mol) is 5.9 J/mm3. I could not figure out how to arrive at the answer. Please help..

You need to convert $mm^3$ to moles or vice-versa. The density of copper is $8.94\,\frac {g}{cm^3}$ . The atomic weight of copper is $65.546\,\frac {g}{mole}$

$\frac {8.94\,g}{cm^3} \times \frac {1\,mole }{65.546\,g} \times \frac {1\,cm^3}{1000\,mm^3} \approx 1.364\times 10^{-4} \,\frac {mole}{mm^3}$

Can you figure it out from there?

Quote:

Originally Posted by Perito

You need to convert $mm^3$ to moles or vice-versa. The density of copper is $8.94\,\frac {g}{cm^3}$ . The atomic weight of copper is $65.546\,\frac {g}{mole}$

$\frac {8.94\,g}{cm^3} \times \frac {1\,mole }{65.546\,g} \times \frac {1\,cm^3}{1000\,mm^3} \approx 1.364\times 10^{-4} \,\frac {mole}{mm^3}$

Can you figure it out from there?

Thank you very much!!

Quote:

Originally Posted by spg25

How to convert enthalpy of fusion (delta H) with units in kJ/mol to J/mm3?

I have a paper which says that enthalpy of fusion of copper (13.01 kJ/mol) is 5.9 J/mm3. I could not figure out how to arrive at the answer. Please help..

work on the relation pV=nRuT where V is the vol in cubic mm and you will able to get the same result in J/mm3

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