Ask Me Help Desk - Expand x^3(x-5)^6 over square root of x-4

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Expand x^3(x-5)^6 over square root of x-4

Expand x^3(x-5)^6 over square root of x-4

Evaluate log[base 6]square root of 6

Quote:

Originally Posted by BigTreeWoody

Expand $\frac {x^3(x-5)^6}{\sqrt {x^{-4}}$

Evaluate $log_6 \left( \sqrt {6} \right)$

Expand $\frac {x^3(x-5)^6}{\sqrt {x^{-4}}$

$\sqrt{x^{-4}}=\sqrt {\frac {1}{x4} }= \frac {1}{x^2}$

You should be able to take it from there.

$log_6 \left( \sqrt {6} \right)=log_6 \left( 6^{\frac 12} \right)$

Now, ask yourself, what does $log_6(x)$ mean? It means the power that 6 has to be raised to in order to get x. So, what power does 6 have to be raised to in order to get $6^{\frac 12}$ (hint: don't think too hard.)?

Quote:

Originally Posted by Perito

Expand $\frac {x^3(x-5)^6}{\sqrt {x^{-4}}$

$\sqrt{x^{-4}}=\sqrt {\frac {1}{x4} }= \frac {1}{x^2}$

You should be able to take it from there.

$log_6 \left( \sqrt {6} \right)=log_6 \left( 6^{\frac 12} \right)$

Now, ask yourself, what does $log_6(x)$ mean? It means the power that 6 has to be raised to in order to get x. So, what power does 6 have to be raised to in order to get $6^{\frac 12}$ (hint: don't think too hard.)?

So what are the answers, Perito?

Hey decent, we're not supposed to directly give the answers here. What if the OP gets the answer right, but has learned nothing? He/She'll not be able to do such questions the day of his/her exams! :mad: I'll PM you the answers if you want to know the solution.

Quote:

Originally Posted by Unknown008

Hey decent, we're not supposed to directly give the answers here. What if the OP gets the answer right, but has learned nothing? He/She'll not be able to do such questions the day of his/her exams! :mad: I'll PM you the answers if you want to know the solution.

Yeah you may send a PM to me! Thanks a lot..! :)

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