Hi
How do we solve an inequality like (x-6) (x +7) > 0
or (y+1) (y) (y-2)(y-4) greater than or equal to 0
thanks in advance
with due regards
Shekhar
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Hi
How do we solve an inequality like (x-6) (x +7) > 0
or (y+1) (y) (y-2)(y-4) greater than or equal to 0
thanks in advance
with due regards
Shekhar
But how did u get to the answer... that is what I want to know... thanks
It's just like solving the individual equations. Don't let the inequalities bug you too much. For example,Quote:
How do we solve an inequality like
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This is already factored. It's not like, which is the same equation unfactored. Since it's already factored, a lot of your work is taken away. Treat it like this equation:
You know that if the product of two terms is equal to zero, one of the terms must be equal to zero. Therefore
and
or
and
Now, since this is an inequality, you put the two answers together using set notation recognizing the boundaries imposed by the inequality.
You do the same with the other equation whose roots of the equality are -1, 0, 2, and 4. Remember that this equation includes the equality (≥ not just >).
In some cases, you can simplify the set terminology. For example, if you find that
, it's easy to show that the second set is entirely enclosed in the first set, so the union of the two sets is simply the second set
Thanks a lot to u both... thx a lot
Now will the same logic hold for the inequality
(x- 5)(x+8)(x - 3) < 0??
Yes, absolutely.
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