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-   -   Solving an inequality (https://www.askmehelpdesk.com/showthread.php?t=356929)

  • May 22, 2009, 10:19 PM
    boraxmatix
    solving an inequality
    Hi
    How do we solve an inequality like (x-6) (x +7) > 0


    or (y+1) (y) (y-2)(y-4) greater than or equal to 0

    thanks in advance

    with due regards

    Shekhar
  • May 23, 2009, 11:01 AM
    galactus
    Quote:

    Originally Posted by boraxmatix View Post
    Hi
    How do we solve an inequality like (x-6) (x +7) > 0




    or
    Quote:






    thanks in advance

    with due regards

    Shekhar[/QUOTE]
  • May 24, 2009, 12:24 AM
    boraxmatix
    But how did u get to the answer... that is what I want to know... thanks
  • May 24, 2009, 04:27 AM
    Perito
    Quote:

    How do we solve an inequality like


    It's just like solving the individual equations. Don't let the inequalities bug you too much. For example,



    This is already factored. It's not like , which is the same equation unfactored. Since it's already factored, a lot of your work is taken away. Treat it like this equation:



    You know that if the product of two terms is equal to zero, one of the terms must be equal to zero. Therefore

    and

    or

    and

    Now, since this is an inequality, you put the two answers together using set notation recognizing the boundaries imposed by the inequality.



    You do the same with the other equation whose roots of the equality are -1, 0, 2, and 4. Remember that this equation includes the equality (≥ not just >).

    In some cases, you can simplify the set terminology. For example, if you find that
    , it's easy to show that the second set is entirely enclosed in the first set, so the union of the two sets is simply the second set
  • May 25, 2009, 12:31 AM
    boraxmatix
    Thanks a lot to u both... thx a lot
  • May 25, 2009, 12:34 AM
    boraxmatix
    Now will the same logic hold for the inequality

    (x- 5)(x+8)(x - 3) < 0??
  • May 25, 2009, 05:16 AM
    Perito

    Yes, absolutely.

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