Ask Me Help Desk - How do I find the foci and vertices from this equation?

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)

- High School (https://www.askmehelpdesk.com/forumdisplay.php?f=400)

- - How do I find the foci and vertices from this equation? (https://www.askmehelpdesk.com/showthread.php?t=353572)

How do i find the foci and vertices from this equation?

So I have the equation y^2/9 - x^2/36=1 how do I find the foci and vertices?

Quote:

y^2/9 - x^2/36=1
How do I find the foci and vertices?

I'll assume this is what you meant:

$\frac {y^2}{9} - \frac {x^2}{36}=1$

The general form of an equation for an ellipse is

$\frac {(x-h)^2}{a^2} + \frac {(y-k)^2}{b^2} = 1$

Equation of Ellipse

Your equation is almost in this form:

$\frac {(x-0)^2}{3^2} + \frac {(y-0)^2}{6^2} = 1$

The center is at (h,k).

See this to determine the foci

Focus of Ellipse. The formula for the focus and ...

(x+2)^2 (y+1)^2
______ - _______ = 1 I'm looking for vertices,foci, and center
169 4

Find the equation for the hyperbola that satisfies the given conditions? For Vertices(0, + or - 7) asymptote y= +or - 1/4.

Find the equation for the hyperbola that satisfies the given conditions? For Vertices(0, + or - 7) asymptote y= +or - 1/4.

My answer was wrong y^2/49-16x^2/49=1
elp to see where I went wrong with this equation.

All times are GMT -7. The time now is 07:58 PM.