Q. Unpolarised light of intensity 30.0W/m^2 passes through a polariser inclined at 35 degrees to the vertical. What is the trnasmitted intensity?
I know that I have to use Malus law, this is my working:
As it is unpolarised, I half 30/2=15
I=I0cos^2θ
= 15cos^2(35)
= 10W/m^2 but the answer is 15W/m^2
Can anyone please help...