(x+4)^2=16(y+2) find the vertex, focus, and directix of the parabola. Graph the equation. I got the vertex, how do find the focus and directix.
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(x+4)^2=16(y+2) find the vertex, focus, and directix of the parabola. Graph the equation. I got the vertex, how do find the focus and directix.
Parabola - Wikipedia, the free encyclopedia gives you a lot of information about parabolas.
Basically, if you arrange the equation for a parabola in this form:
or
The vertex is (x,k); the focus is (h, k+p); the directrix is y=k-p where p is the distance from the vertex to the focus.
Is your equation in this form?
If it is, you should be able to pick out the values directly. The + and/or - signs shouldn't throw you. If you had (x+7)^2, h is simply -7.
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