A 200-N sled is pushed along a horizontal surface at constant speed with a 50-N force that makes an angle of 28 degrees below the horizontal. What is the coefficient of kinetic fricition?
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A 200-N sled is pushed along a horizontal surface at constant speed with a 50-N force that makes an angle of 28 degrees below the horizontal. What is the coefficient of kinetic fricition?
This may assist
http://www.ap.stmarys.ca/demos/conte..._friction.html
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component of 50 N along direction of motion = 50cos28= 44.14 N
coefficient of friction = 44.14/200 = 0.2207
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