1) NaOH(s)--> Na+(aq) + OH- (aq)
2) Na+(aq) + OH(aq) + H+(aq) + Cl-(aq) --> H2O + Na+(aq) + Cl-(aq)

Target
equation: NaOH(s) + H+(aq) + Cl(aq)--> H20 + Na+(aq) + Cl-(aq)

I need help solving this.. Thanks

Quote:

---

Originally Posted by lorijessica16

1) NaOH(s)--> Na+(aq) + OH- (aq)
2) Na+(aq) + OH(aq) + H+(aq) + Cl-(aq) --> H2O + Na+(aq) + Cl-(aq)

Target
equation: NaOH(s) + H+(aq) + Cl-(aq)--> H20 + Na+(aq) + Cl-(aq)

---

Actually, it appears you have solved it.







therefore, adding them together and eliminating redundancies on both sides of the "-->",



Depending on how you wish to express it, you can write it this way:



In this case, you don't emphasize that the NaCl is dissociated. If you wish to emphasize that NaOH and HCl are dissociated you can write this:



But the Na+ and Cl- on both sides of the equation is sort of silly. They're simply "spectator ions".




I'm not sure how this relates to Hess's law which is about energy changes.